Cómo comprobar si dos cadenas son anagramas entre sí

Un anagrama es una cadena formada reordenando las letras de una cadena diferente. Verificar si dos cadenas son anagramas entre sí puede parecer difícil, pero es solo un poco complicado y engañosamente sencillo. En este artículo, aprenderá a verificar si dos cadenas son anagramas entre sí usando C ++, Python y JavaScript.

Planteamiento del problema

Te dan dos cadenas s1 y s2, necesitas verificar si las dos cadenas son anagramas entre sí o no.

Ejemplo 1 : Sea s1 = "creativo" y s2 = "reactivo".

Dado que la segunda cadena se puede formar reorganizando las letras de la primera cadena y viceversa, las dos cadenas son anagramas entre sí.

Ejemplo 2 : Sea s1 = "Peter Piper recogió un pimiento de pimientos en escabeche" y s2 = "Un picoteo de pimientos en escabeche recogió Peter Piper".

Dado que la segunda cadena no se puede formar reorganizando las letras de la primera cadena y viceversa, las dos cadenas no son anagramas entre sí.

Proceso para verificar si dos cadenas son anagramas entre sí

Puede seguir el enfoque a continuación para verificar si las dos cadenas son anagramas entre sí:

  1. Compara la longitud de ambas cuerdas.
  2. Si la longitud de ambas cadenas no es la misma, significa que no pueden ser anagramas entre sí. Por lo tanto, devuelve falso.
  3. Si la longitud de ambas cadenas es la misma, continúe.
  4. Ordene ambas cadenas.
  5. Compare ambas cadenas ordenadas.
  6. Si ambas cadenas ordenadas son iguales, significa que son anagramas entre sí. Por lo tanto, devuelve verdadero.
  7. Si ambas cadenas ordenadas son diferentes, significa que no son anagramas entre sí. Por lo tanto, devuelve falso.

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Programa C ++ para comprobar si dos cadenas son anagramas entre sí

A continuación se muestra el programa C ++ para comprobar si dos cadenas son anagramas entre sí o no:

 #include <bits/stdc++.h>
using namespace std;
bool checkAnagrams(string s1, string s2)
{
int size1 = s1.length();
int size2 = s2.length();
// If the length of both strings are not the same,
// it means they can't be anagrams of each other.
// Thus, return false.
if (size1 != size2)
{
return false;
}
sort(s1.begin(), s1.end());
sort(s2.begin(), s2.end());
for (int i = 0; i < size1; i++)
{
if (s1[i] != s2[i])
{
return false;
}
}
return true;
}
int main()
{
string s1 = "listen";
string s2 = "silent";
cout << "String 1: " << s1 << endl;
cout << "String 2: " << s2 << endl;
if(checkAnagrams(s1, s2))
{
cout << "Yes, the two strings are anagrams of each other" << endl;
}
else
{
cout << "No, the two strings are not anagrams of each other" << endl;
}
string s3 = "Welcome to MUO";
string s4 = "MUO to Welcome";
cout << "String 3: " << s3 << endl;
cout << "String 4: " << s4 << endl;
if(checkAnagrams(s3, s4))
{
cout << "Yes, the two strings are anagrams of each other" << endl;
}
else
{
cout << "No, the two strings are not anagrams of each other" << endl;
}
string s5 = "Peter Piper picked a peck of pickled peppers";
string s6 = "A peck of pickled peppers Peter Piper picked";
cout << "String 5: " << s5 << endl;
cout << "String 6: " << s6 << endl;
if(checkAnagrams(s5, s6))
{
cout << "Yes, the two strings are anagrams of each other" << endl;
}
else
{
cout << "No, the two strings are not anagrams of each other" << endl;
}
string s7 = "She sells seashells by the seashore";
string s8 = "seashells by the seashore";
cout << "String 7: " << s7 << endl;
cout << "String 8: " << s8 << endl;
if(checkAnagrams(s7, s8))
{
cout << "Yes, the two strings are anagrams of each other" << endl;
}
else
{
cout << "No, the two strings are not anagrams of each other" << endl;
}
string s9 = "creative";
string s10 = "reactive";
cout << "String 9: " << s9 << endl;
cout << "String 10: " << s10 << endl;
if(checkAnagrams(s9, s10))
{
cout << "Yes, the two strings are anagrams of each other" << endl;
}
else
{
cout << "No, the two strings are not anagrams of each other" << endl;
}
return 0;
}

Producción:

 String 1: listen
String 2: silent
Yes, the two strings are anagrams of each other
String 3: Welcome to MUO
String 4: MUO to Welcome
Yes, the two strings are anagrams of each other
String 5: Peter Piper picked a peck of pickled peppers
String 6: A peck of pickled peppers Peter Piper picked
No, the two strings are not anagrams of each other
String 7: She sells seashells by the seashore
String 8: seashells by the seashore
No, the two strings are not anagrams of each other
String 9: creative
String 10: reactive
Yes, the two strings are anagrams of each other

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Programa Python para verificar si dos cadenas son anagramas entre sí

A continuación se muestra el programa Python para verificar si dos cadenas son anagramas entre sí o no:

 def checkAnagrams(s1, s2):
size1 = len(s1)
size2 = len(s2)
# If the length of both strings are not the same,
# it means they can't be anagrams of each other.
# Thus, return false.
if size1 != size2:
return 0
s1 = sorted(s1)
s2 = sorted(s2)
for i in range(0, size1):
if s1[i] != s2[i]:
return False
return True

s1 = "listen"
s2 = "silent"
print("String 1: ", s1)
print("String 2: ", s2)
if(checkAnagrams(s1, s2)):
print("Yes, the two strings are anagrams of each other")
else:
print("No, the two strings are not anagrams of each other")
s3 = "Welcome to MUO"
s4 = "MUO to Welcome"
print("String 3: ", s3)
print("String 4: ", s4)
if(checkAnagrams(s3, s4)):
print("Yes, the two strings are anagrams of each other")
else:
print("No, the two strings are not anagrams of each other")
s5 = "Peter Piper picked a peck of pickled peppers"
s6 = "A peck of pickled peppers Peter Piper picked"
print("String 5: ", s5)
print("String 6: ", s6)
if(checkAnagrams(s5, s6)):
print("Yes, the two strings are anagrams of each other")
else:
print("No, the two strings are not anagrams of each other")
s7 = "She sells seashells by the seashore"
s8 = "seashells by the seashore"
print("String 7: ", s7)
print("String 8: ", s8)
if(checkAnagrams(s7, s8)):
print("Yes, the two strings are anagrams of each other")
else:
print("No, the two strings are not anagrams of each other")
s9 = "creative"
s10 = "reactive"
print("String 9: ", s9)
print("String 10: ", s10)
if(checkAnagrams(s9, s10)):
print("Yes, the two strings are anagrams of each other")
else:
print("No, the two strings are not anagrams of each other")

Producción:

 String 1: listen
String 2: silent
Yes, the two strings are anagrams of each other
String 3: Welcome to MUO
String 4: MUO to Welcome
Yes, the two strings are anagrams of each other
String 5: Peter Piper picked a peck of pickled peppers
String 6: A peck of pickled peppers Peter Piper picked
No, the two strings are not anagrams of each other
String 7: She sells seashells by the seashore
String 8: seashells by the seashore
No, the two strings are not anagrams of each other
String 9: creative
String 10: reactive
Yes, the two strings are anagrams of each other

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Compruebe si dos cadenas son anagramas entre sí en JavaScript

A continuación se muestra el programa JavaScript para verificar si dos cadenas son anagramas entre sí o no:

 function checkAnagrams(s1, s2) {
let size1 = s1.length;
let size2 = s2.length;
// If the length of both strings are not the same,
// it means they can't be anagrams of each other.
// Thus, return false.
if (size1 != size2)
{
return false;
}
s1.sort();
s2.sort();
for (let i = 0; i < size1; i++)
{
if (s1[i] != s2[i])
{
return false;
}
}
return true;
}

var s1 = "listen";
var s2 = "silent";
document.write("String 1: " + s1 + "<br>");
document.write("String 2: " + s2 + "<br>");
if(checkAnagrams(s1.split(""), s2.split(""))) {
document.write("Yes, the two strings are anagrams of each other" + "<br>");
} else {
document.write("No, the two strings are not anagrams of each other" + "<br>");
}
var s3 = "Welcome to MUO";
var s4 = "MUO to Welcome";
document.write("String 3: " + s3 + "<br>");
document.write("String 4: " + s4 + "<br>");
if(checkAnagrams(s3.split(""), s4.split(""))) {
document.write("Yes, the two strings are anagrams of each other" + "<br>");
} else {
document.write("No, the two strings are not anagrams of each other" + "<br>");
}
var s5 = "Peter Piper picked a peck of pickled peppers";
var s6 = "A peck of pickled peppers Peter Piper picked";
document.write("String 5: " + s5 + "<br>");
document.write("String 6: " + s6 + "<br>");
if(checkAnagrams(s5.split(""), s6.split(""))) {
document.write("Yes, the two strings are anagrams of each other" + "<br>");
} else {
document.write("No, the two strings are not anagrams of each other" + "<br>");
}
var s7 = "She sells seashells by the seashore";
var s8 = "seashells by the seashore";
document.write("String 7: " + s7 + "<br>");
document.write("String 8: " + s8 + "<br>");
if(checkAnagrams(s7.split(""), s8.split(""))) {
document.write("Yes, the two strings are anagrams of each other" + "<br>");
} else {
document.write("No, the two strings are not anagrams of each other" + "<br>");
}
var s9 = "creative";
var s10 = "reactive";
document.write("String 9: " + s9 + "<br>");
document.write("String 10: " + s10 + "<br>");
if(checkAnagrams(s9.split(""), s10.split(""))) {
document.write("Yes, the two strings are anagrams of each other" + "<br>");
} else {
document.write("No, the two strings are not anagrams of each other" + "<br>");
}

Producción:

 String 1: listen
String 2: silent
Yes, the two strings are anagrams of each other
String 3: Welcome to MUO
String 4: MUO to Welcome
Yes, the two strings are anagrams of each other
String 5: Peter Piper picked a peck of pickled peppers
String 6: A peck of pickled peppers Peter Piper picked
No, the two strings are not anagrams of each other
String 7: She sells seashells by the seashore
String 8: seashells by the seashore
No, the two strings are not anagrams of each other
String 9: creative
String 10: reactive
Yes, the two strings are anagrams of each other

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